Mike
Sounds like an excellent solution to me
Three very minor comments:
I looked at the HP23 schematic that is posted on the BAMA web site.
In the posted schematic, each half of the voltage doubler uses 125uF in parallel with 50k ohms (a pair of 100k ohm resistors in parallel). The capacitors in the HP23 will bleed down with a time constant of 125 uF x 50 k ohms = 6.25 seconds. Therefore, the voltage will decay to 5% of its full value in 18.75 seconds
In your new design, the capacitors in each half of the voltage doubler will bleed down with a time constant of 160 uF x 100k ohms = 16 seconds. Therefore, it will take 48 seconds for the voltage to decay to 5% of its full value.
So... if you are going to work on the supply or anything connected to the supply...you need to make sure that you wait 48 seconds, instead of 19 seconds, before you use your insulated / grounded safety discharge stick to short the HV output to ground.
Each 3 watt resistor will dissipate up to 3 watts, so your total bleeder design is good for 12 watts.
Each 200k ohm resistor will have to dissipate approximately 400 volts x 400 volts / 200,000 ohms = 0.8 watts ... so your 3 watt resistors should be very comfortable.
Since this is a voltage doubler design, the output voltage will split evenly across the two capacitors even if the leakage resistance of one or both of the capacitors is not swamped by your bleeder resistors. In effect, each capacitor is being charged independently by the transformer on each AC cycle.
Best regards
Stu