Steve,
Thanks for taking the time to write these lengthy explanations. A couple of questions:
What is meant by "plate to plate" in the context of impedance for example: "...plate to plate impedance of 9500 ohms ..."
I am unfamiliar with this experssion. It sounds like it means modulator plates to RF PA plate(s) but I have trouble understanding that since in the path there is a mod. transformer with a Z ratio. Then there is a power supply choke in the path which I guess must have some impedance and the tube anode impedance.
My other question has to do with the problem of getting the modulator voltage to zero. I thought the modulator v. had to swing from B+ acrross zero to the negative value of B+ to cut off the carrier.
thanks,
Rob
Frank pretty much hit it! The plate-to-plate impedance is the transformer primary impedance, which is dependant on the load on the secondary. So, a transformer with a 1.5:1 impedance ratio, if presented with 5000 ohms across the secondary, will present a 7500 ohm load across the primary (full primary, which is plate-to-plate), and this is the impedance the modulator tube are working into.
The actual impedance is not so much of concern as is the RATIO. The voltage ratio (also the turns ratio - the same thing) is the square root of the impedance ratio.
The actual impedance comes into play in 2 areas:
1) Can the modulator tubes deliver the required power into whatever primary impedance is presented to the modulator tubes? Can the tubes pull the peak current required; do they have the plate dissipation; can they handle the voltage, etc....
2) Can the transformer operate at the impedance in question --> transformer voltage, current, capacitance and inductance all all factors here.
The voltage swing at the primary of the transformer will vary from approximately 0V using an ideal modulator triode, to approximately twice the B+ under the same conditions. When the tube on one side of the transformer primary is turned on hard, and approaches 0V, the tube on the other side of the primary (turned off) will experience appximately twice the B+ at its plate.
At the secondary, the voltage across the secondary will depend on the turns ratio of the transformer, and will be an AC waveform, reversing polarity every half cycle. The voltage across the secondary is added to, or subtracted from, the DC voltage that is delivered to the load, either through the transformer secondary itself, or coupled to the load through a capacitor/inductor combination (so-called "modified Heising").
Hope this also helps!
Regards,
Steve