I think I see that with a perfect match p would be zero.

Probably not much help,

Fred

Just re-read your last question, I'm not getting how the reflected wave reaching the matched input gets fully reflected (p=1). I always thought it gets absorbed by the matched input.

Maybe I'm not understanding something.

I think I also see where p would be the absolute value because I think I see where p could be a negative number when Z(line) is greater than Z(load).

Been a while since I did any math with complex numbers.]]>

Walt Maxwell, in his book Reflections II, extensively discusses transmission-line reflections. In Appendix 7-1, discussing the transmission line conjugately driven by a matched source, [ eg: Z(source) = R + jX and Z(line) = R- jX ]]>]]

“The reflection at the mismatch gives rise to a second wave that travels back to the input of the line with the magnitude determined by multiplying the magnitude of the initial wave by the magnitude of [the reflection coefficient]]>]

Now I’ve read this idea enough times, in enough places, by enough authors, in enough different wording, that it would seem foolhardy to disbelieve it. But! Back on page 3-1, Maxwell states in Eq. 3-1 that:

ρ = [ Z(load) - Z(line ]]>]]

I’ve also seen that equation in lots of places, and in a conjugate-matched system, this equation, I believe, ends up with a zero numerator, and thus equates to zero.

And if so, how do I correlate p = 0 here with Maxwell’s later statement that the conjugate match at a line input gives ρ = 1? Was he lying in Chapter 3 or is he lying in Appendix 7?

Ok, ok, so Walt didn’t lie. Where am I missing the boat? How does a first reflection from a mismatched load, arriving at the conjugately-matched line input, get fully reflected?

-al hart,

al@w8vr.org]]>

The Stancor P-8405 or similar looks the best (540 vac CT @ 120 ma, 5v Fil, 6.3 v @ 3.5A).

Anyone got one lurking in the Olde Junque Boxe ??

Tnx es HH, Dick, W1KSZ]]>

john N8QPC]]>