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THE AM BULLETIN BOARD => Technical Forum => Topic started by: KE7NL - Jack on December 10, 2006, 11:01:31 AM



Title: Kenyon T-489
Post by: KE7NL - Jack on December 10, 2006, 11:01:31 AM
In my Junque Box resides a Kenyon T-489.  The "Transformer" info on AM Window brackets that part number.  From it's physical size, I would say it is some sort of interstage device.  Can anyone tell me what it is? -- specifications? -- pin out?

TNX
JAS


Title: Re: Kenyon T-489
Post by: WBear2GCR on December 10, 2006, 11:39:02 AM
I do not have the info on that iron.

But you can experimentally determine the specs.

An ohmeter will give you the DCR and so the winding arrangement.

Then placing a low voltage on the lowest DCR winding will give you the overall turns ratio.

If you put 1 volt AC or 10 volts AC then the turns ratio can be read out directly by the voltmeter on the secondary.  60Hz from a wall wart is sufficient.

Then use the standard equation for turns ratio : impedance ratio to find that.
The power can be guesstimated by the core size.

A comparison of the DCR of the low impedance side (assuming it's not a 1:1) to a known transformer's DCR of similar size will get you in the ball park for the original intended impedances.

Sweeping with an audio signal, using an appropriate terminating resistor will get you back the bandwidth and also help to pinpoint the optimal impedance ratio.

There's probably a better way to determine the original intended impedance ratios, but I'm not sure what that would be.

       _-_-WBear2GCR


Title: Re: Kenyon T-489
Post by: Jim, W5JO on December 10, 2006, 02:49:49 PM
Kenyon T-489. is a 15 watt primary to 30 watt seconday modulation transformer.

Primary is 2K to 20K to a class C 200 to 20K.

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