Transmission Line Question

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KA2DZT:
Some folks completely agree with Maxwell's work.  There also is a lot of folks that don't agree.  I think the reflected wave is added to the incident wave and the sum of the two waves are sent back to the load.  Phase difference determines what the sum of the two waves ends up being.  So the reflected wave does return to the load.

Suppose a single cycle pulse was transmitted to the load.  The reflected wave would then return to a passive transmitter.  What happens to the reflected wave??  Assume a perfect match between the transmitter and transmission line.  Mismatch at the load.

Fred

Steve - K4HX:
How could the source be matched and the load not be and no "tuner" be involved?

Quote

What if there is no "tuner"? If the source and line are matched at the source end, and a mismatch is present at the load end the resulting reflected wave will see p=0 at source.

ashart:
Steve:

Would any source with a Thevenin internal impedance of Z = 50 + j0 not do the job or am I misunderstanding your question?

-al hart
al@w8vr.org

WD8BIL:
Should have been more detailed Steve. Source, 50 ohms - Line, 50 ohms - Load, something other than 50.

This puts the mismatch at the load end of the line (which has an impedance of it's own) not at the source. Splitting hairs??? Perhaps!

Steve - K4HX:
If the source is 50 Ohms and the line is also 50 Ohm but the load is not, there will be a mismatch at the source.  Example:

50 Ohm source driving 100 feet of RG213 with 200 Ohms connected at the far end - the Z seen by the source will be 105 - j80.

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